Appendix : Developing a Test Taking Strategy
9
calculate the problem you forget to account for the roundtrip effect,
this should have given you a big clue to recalculate your answer.)
10. Which of the following sequences is in correct decreasing
order?
A.
G, M,
µ
, n, k
B.
G, M, k, c,
µ
C.
n,
µ
, c, k, G
D.
G, M, k, n,
µ
E.
n, m, c, m, G
Question Type:
Peek
Keywords:
decreasing
Central concept:
memorization of metric abbreviations
Write down the entire sequence on scrap paper. You will then
be able to use this paper as a reference for other related ques-
tions
n, μ, m, c, d, da, h, k, M, G
(Note that the answer must be in decreasing order!)
Now match the choices with your sequence.
Eliminate C and E immediately because they are in an
increasing order, not decreasing order!
Only choice B is in the correct decreasing order.
11. Which of the following is not true?
A. axial resolution = SPL/2
B. lateral resolution = beamwidth/2
C. axial resolution is improved by the use of a backing
material
D. lateral resolution can be improved in the near field by
focusing
E. a deeper focuses generally creates better sensitivity to
deep structures
Question Type:
Look
Keywords:
not true
Choice B is not true: lateral resolution = beamwidth.
Since the question asks for which choice is not true,
Choice
B is the correct response.
(Note: This type of question is very useful, since there is information
which can be used elsewhere in the exam.)
12. Which of the following results from using a higher frequency
transducer?
A. a longer spatial pulse length
B. a broader beamwidth
C. greater bandwidth
D. a shorter period
E. better sensitivity to deep structures
Question Type:
No Look
Keywords:
using a higher frequency
Central Concept:
This question should be treated as a no look,
because you should be able to predict all of
the effects of using a higher frequency trans-
ducer. A higher frequency means a shorter
period, a shorter pulse duration, a shorter
spatial pulse length, a potentially greater
bandwidth, a potentially better longitudinal
resolution, potentially better lateral resolu-
tion, and a loss of penetration.
Comparing the choices to what you have written down leaves
choosing between a greater bandwidth and a shorter period. A
higher frequency always creates a shorter period, whereas the
bandwidth is not determined just by using a higher frequency,
but also by the transducer design.
Therefore, the better answer
is D, a shorter period.